#Write a progran that reads one 10-digit integer, 
#and finds and prints the average of its EVEN digits. 
#If there are no even 
#digits in the parameter, the function prints 
#an appropriate message. 
#USE LOOP FOR

#example: num=3456741456
#digit=num%10=3456741456%10=6
#num=num//10=3456741456//10=345674145
#digit=345674145%10=

def main():
	num=int(input("enter 10-digit number "))
	sumEven=0
	counterEven=0
	for i in range(10):
		digit=num%10
		if(digit%2==0):
			sumEven=sumEven+digit
			counterEven=counterEven+1
		num=num//10


	if(counterEven>0):
		average=sumEven/counterEven
		print("average of evens is",average)
	else:
		print("no even digits")
main()