#treasure chest has 3-digit lock
#open conditions: all numbers are odd
#sum is divisible by 3
#last digit is larger or equal than 5


#write a program that process 3 different 
#lock combinations

def main():
	lock_combination=int(input("enter 3-digit num "))
	
	if(lock(lock_combination)):
		print("YES")
	else:
		print("NO")

	lock_combination=int(input("enter 3-digit num "))
	if(lock(lock_combination)):
		print("YES")
	else:
		print("NO")

	lock_combination=int(input("enter 3-digit num "))
	if(lock(lock_combination)):
		print("YES")
	else:
		print("NO")

def lock(num):
	last=num%10
	num=num//10
	mid=num%10
	num=num//10
	first=num%10

	odd1=(last%2!=0)
	odd2=(mid%2!=0)
	odd3=(first%2!=0)
	cond_odd=odd1 and odd2 and odd3
	cond_sum=((last+mid+first)%3==0)
	cond_last=(last>=5)

	if(cond_odd and cond_sum and cond_last):
		result=True
	else:
		result=False
	
	return result
#this function returns BOOLEAN type of variable True or False
main()