#Write a program that reads one three-digit positive integer
#and prints its digits on separate line
#Input is ONE number between 100 and 999
#Process: Example: suppose our input is 234
#234%10 = 4 - last digit
#234//10 = 23
#23%10 = 3 - middle digit
#23//10=2
#2%10 = 2 - fist digit
#Example: 780
#780%10 = 0 - LAST digit
#780//10 = 78
#78%10 = 8 - Middle digit
#78//10 = 7
#7%10 = 7 - First digit
#Example: 981
#981%10 = 1 - LAST digit
#981//10 = 98
#98%10 = 8 - Middle digit
#98//10 = 9
#9%10 = 9 - First Digit
#Part I Input
num = int(input("Enter positive 3-digit number "))
save_num = num #to preserve the original input value
#Part 2 Calculations
#to hold the output we need at least variables
lastDigit = num%10
num = num//10 
#the original value will be divided by 10
#and the new result will OVERWRITE the original value
middleDigit = num%10
num=num//10
firstDigit = num%10
print("my digits are:")
print(firstDigit)
print(middleDigit)
print(lastDigit) 

print("The value of variable num is", num)
#How can we preserve an original input value???

print("the value of save_num is", save_num)