#Write a program that reads 10-digit integer, and finds and prints the 
#average of its EVEN digits. If there are no even digits in the input, the 
#program prints an appropriate message. 

#Input: ONE input - ONE 10-digits integer, for example 7856789654 

num=int(input("enter ONE 10-digit integer "))
i=1
count_even=0
sum_even=0

while(i<=10):
	digit=num%10
	num=num//10
	if(digit%2==0):
		count_even=count_even+1
		sum_even=sum_even+digit
	i=i+1

if(count_even>0):
	print("there are", count_even,"even digits")
	print("their sum is",sum_even)
	print("their average is", sum_even/count_even)
else:
	print("no even digits")