/* Write a function int count_last5 (int A[], int size) 

that finds and returns the number of elements in the array whose last digit is equal to 5.

Then, write a program that:

    Randomly generates an array of 10 integers, each between 1 and 500.

    Prints the randomly generated array.

    Calls the count_last5 function and prints the 
number of integers in the array whose last digit is 5. 
Hint: to find last digit of num, use num%10.
*/
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
#define SIZE 10
int count_last5 (int A[], int size);
void make_random_array(int A[], int size, int min, int max);
void print_array(int A[], int size);
int main(){
	int A[SIZE];
	srand(time(NULL));
	make_random_array(A, SIZE, 0,500);
	print_array(A, SIZE);
	printf("the number of ints with last digit 5 is %d\n", count_last5(A, SIZE));

}
int count_last5(int A[], int size){
	int i, count=0;
	for(i=0;i<size;i++){
		if(A[i]%10==5)
			count++;
	}
	return count;
}
void make_random_array(int A[], int size, int min, int max){
	
	int i;
	for(i=0;i<size;i++){
		A[i]=min+rand()%(max-min+1);
	}
}
void print_array(int A[], int size){
	int i;
        for(i=0;i<size;i++){
		printf("%d ",A[i]);
	}
	printf("\n");
}