- Convert binary number 1100 1101 to decimal
Solution: add power of 2 that corresponds to the bits that are ON ( bits that are equal 1):
128 + 64 + 8 + 4 + 1 = 205
Final answer: 205 is decimal equivalent of binary number 1100 1101
- Convert decimal 38 to binary:
Solution Method 1:
128 fits into 38? NO b7 = 0
64 fits into 38? NO b6 = 0
32 fits into 38? YES b5 = 1
38 - 32 = 6
Continue with 6:
16 fits into 6? NO b4 = 0
8 fits into 6? NO b3 = 0
4 fits into 6 YES b2 = 1
6 - 4 = 2
Continue with 2:
2 fits into 2? YES b1 = 1
2-2 = 0
Continue with 0:
1 fits into 0? NO b0 = 0
Final answer: Decimal number 38 in binary is 0010 0110
Method 2 using Integer Division and Remainder:
38 / 2 = 19 remainder 0 b0 = 0
19 / 2 = 9 remainder 1 b1 = 1
9 / 2 = 4 remainder 1 b2 = 1
4 / 2 = 2 remainder 0 b3 = 0
2 / 2 = 1 remainder 0 b4 = 0
1 / 2 = 0 remainder 1 b5 = 1
As soon as we got 0 the process is stopped and the rest of the bits are 0: b6 = 0, b7 =0
Final Answer: Decimal number 38 in binary system is: 0010 0110
- Convert binary number 0100 0100 to decimal
Solution: add power of 2 that corresponds to the bits that are ON ( bits that are equal 1):
64 + 4 = 68
Final answer: 68 is decimal equivalent of binary number 0100 0100
- Convert decimal 121 to binary:
Solution Method 1:
128 fits into 121? NO b7 = 0
64 fits into 121? YES b6 = 1
121 - 64 = 57
Continue with 57
32 fits into 57? YES b5 = 1
57 - 32 = 25
Continue with 25:
16 fits into 25? YES b4 = 1
25 - 16 = 9
Continue with 9
8 fits into 9? YES b3 = 1
9 - 8 = 1
Continue with 1
4 fits into 1? NO b2 = 0
2 fits into 1? NO b1 = 0
1 fits into 1? YES b0 = 1
Final answer: Decimal number 121 in binary is 0111 1001
Method 2 using Integer Division and Remainder:
121 / 2 = 60 remainder 1 b0 = 1
60 / 2 = 30 remainder 0 b1 = 0
30 / 2 = 15 remainder 0 b2 = 0
15 / 2 = 7 remainder 1 b3 = 1
7 / 2 = 3 remainder 1 b4 = 1
3 / 2 = 1 remainder 1 b5 = 1
1 / 2 = 0 remainder 1 b6 = 1
As soon as we got 0 the process is stopped and the rest of the bits are 0:b7 =0
Final Answer: Decimal number 121 in binary system is: 0111 1001
Convert Go! to binary
Solution: Go! in ASCII is: 71 111 33
71 to binary:
71/2 = 35 b0 = 1
35/2 = 17 b1 = 1
17/2 = 8 b2 = 1
8/2 = 4 b3 = 0
4/2 = 2 b4 = 0
2/2 = 1 b5 = 0
1/2 = 0 b6 = 1
71 in binary: 0100 0111
111 in binary: 0110 1111
33 in binary: 0010 0001
Final answer: Go! in binary: 01000111 01101111 00100001
- Decode: 01101101 01000101 00110010
Solution: converting each BYTE to decimal
0110 1101 adding powers of 2 that are ON: 64 + 32 + 8 + 4 + 1 = 109
0100 0101 is 69
0011 0010 is 50
Original message in ASCII 109 69 50
Final answer: decoded word: mE2
Programming with Python
Online Resource
Input and Formatted Output in Python:
- For integers use: int(input("user
prompt
"))
- For floats use: float(input("user prompt "))
- For strings
use: input("user prompt ") and when inputing the string you must enclose
it in double or single quotes
- For formatted output use function
format.
- For example, to print only 2 decimal digits of
the number 1232.566777 use the following statement:
print(format(1232.566777, '.2f'))
- For example, to print
only 4 decimal digits of the number 1232.566777 use the following
statement:
print(format(1232.566777, '.4f'))